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42a^2-26a+4=0
a = 42; b = -26; c = +4;
Δ = b2-4ac
Δ = -262-4·42·4
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2}{2*42}=\frac{24}{84} =2/7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2}{2*42}=\frac{28}{84} =1/3 $
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